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birthday mod für 2.0.6.

Verfasst: 07.09.2003 22:02
von Spidy
Hi brauche mal Hilfe könnte das mir mal bitte einer Übersetzen.

Code: Alles auswählen

//Added birthday mod
$lang['Birthday_required'] = 'Force users to submit a birthday';
$lang['Enable_birthday_greeting'] = 'Enable birthday greetings';
$lang['Birthday_greeting_expain'] = 'Users who have submitted a birthday can have a birthday greeting, when thy visit the board';
$lang['Next_birthday_greeting'] = 'Next birthday popup year';
$lang['Next_birthday_greeting_expain'] = 'This field keeps track of the next year the user shall have a birthday greeting';
$lang['Wrong_next_birthday_greeting'] = 'The supplied, next birthday popup year, was not valid, please try again';
$lang['Max_user_age'] = 'Maximum user age';
$lang['Min_user_age'] = 'Minimum user age';
$lang['Birthday_lookforward'] = 'Birthday look forward';
$lang['Birthday_lookforward_explain'] = 'Number of days the script shall look forward for users with a birthday';
Und das Bitte auch noch

Code: Alles auswählen

//Add on for Birthday Mod
$lang['Birthday'] = 'Birthday';
$lang['No_birthday_specify'] = 'None Specified';
$lang['Age'] = 'Age';
$lang['Birthday_explain'] = 'The syntax used is %s, e.g. %s, remember prefixed zeros';
$lang['Wrong_birthday_format'] = 'The birthday format was entered incorrectly.'; 
$lang['Birthday_to_high'] = 'Sorry, this site, does not accept user older than %d years old';
$lang['Birthday_require'] = 'your Birthday are required on this site';
$lang['Birthday_to_low'] = 'Sorry, this site, does not accept user yonger than %d years old';
$lang['Submit_date_format'] = 'd-m-Y'; //php date() format - Note: ONLY d, m and Y may be used and SHALL ALL be used (different seperators are accepted)
$lang['Birthday_greeting_today'] = 'We would like to wish you congratulatons on reaching %s years old today.<br /><br /> The Management';//%s is substituted with the users age
$lang['Birthday_greeting_prev'] = 'We would like to give you a belated congratulatons for becoming %s years old on the %s.<br /><br /> The Management';//%s is substituted with the users age, and birthday
$lang['Greeting_Messaging'] = 'Congratulations';
$lang['Birthday_today'] = 'Users with a birthday today:';
$lang['Birthday_week'] = 'Users with a birthday within the next %d days:';
$lang['Nobirthday_week'] = 'No users are having a birthday in the upcoming %d days'; // %d is substitude with the number of days
$lang['Nobirthday_today'] = 'No users have a birthday today';
$lang['Year'] = 'Year';
$lang['Month'] = 'Month';
$lang['Day'] = 'Day';
// NOTE: Please do not translate the folowing 4 lines !, they are automatically translated into your language
$lang['day_short'] = array ($lang['datetime']['Sun'],$lang['datetime']['Mon'],$lang['datetime']['Tue'],$lang['datetime']['Wed'],$lang['datetime']['Thu'],$lang['datetime']['Fri'],$lang['datetime']['Sat']);
$lang['day_long'] = array ($lang['datetime']['Sunday'],$lang['datetime']['Monday'],$lang['datetime']['Tuesday'],$lang['datetime']['Wednesday'],$lang['datetime']['Thursday'],$lang['datetime']['Friday'],$lang['datetime']['Saturday']);
$lang['month_short'] = array ($lang['datetime']['Jan'],$lang['datetime']['Feb'],$lang['datetime']['Mar'],$lang['datetime']['Apr'],$lang['datetime']['May'],$lang['datetime']['Jun'],$lang['datetime']['Jul'],$lang['datetime']['Aug'],$lang['datetime']['Sep'],$lang['datetime']['Oct'],$lang['datetime']['Nov'],$lang['datetime']['Dec']);
$lang['month_long'] = array ($lang['datetime']['January'],$lang['datetime']['February'],$lang['datetime']['March'],$lang['datetime']['April'],$lang['datetime']['May'],$lang['datetime']['June'],$lang['datetime']['July'],$lang['datetime']['August'],$lang['datetime']['September'],$lang['datetime']['October'],$lang['datetime']['November'],$lang['datetime']['December']);
Danke schon mal im voraus

Verfasst: 07.09.2003 22:27
von Henne

Verfasst: 07.09.2003 22:46
von Spidy
Recht Hertzlichen Dank dafür :D :D