Ich möchte den Easy-Subforum-mod installieren, aber in meinem SEO-phpbb gibt es offenbar einen kleinen Unterschied in der index.php
Es gibt den gesuchten Teil so nicht.
#
#-----[ OPEN ]------------------------------------------------
#
index.php
#
#-----[ FIND ]------------------------------------------------
#
$sql = "SELECT f.*, p.post_time, p.post_username, u.username, u.user_id
FROM (( " . FORUMS_TABLE . " f
LEFT JOIN " . POSTS_TABLE . " p ON p.post_id = f.forum_last_post_id )
LEFT JOIN " . USERS_TABLE . " u ON u.user_id = p.poster_id )
ORDER BY f.cat_id, f.forum_order";
#
#-----[ REPLACE WITH ]----------------------------------------
#
// Modified by Easy Sub-Forums MOD
$sql = "SELECT f.*, p.post_time, p.post_username, u.username, u.user_id, t.topic_id, t.topic_title
FROM ((( " . FORUMS_TABLE . " f
LEFT JOIN " . POSTS_TABLE . " p ON p.post_id = f.forum_last_post_id )
LEFT JOIN " . USERS_TABLE . " u ON u.user_id = p.poster_id )
LEFT JOIN " . TOPICS_TABLE . " t ON t.topic_last_post_id = f.forum_last_post_id)
GROUP BY f.forum_id ORDER BY f.cat_id, f.forum_order";
// END Modified by Easy Sub-Forums MOD
Es gibt allenfalls den Part
Was nun?$sql = "SELECT f.*, p.post_time, p.post_username, u.username, u.user_id, t.topic_title, t.topic_last_post_id " .
" FROM ((( " . FORUMS_TABLE . " f " .
" LEFT JOIN " . POSTS_TABLE . " p ON p.post_id = f.forum_last_post_id )" .
" LEFT JOIN " . USERS_TABLE . " u ON u.user_id = p.poster_id ) " .
" LEFT JOIN " . TOPICS_TABLE . " t ON t.topic_last_post_id = p.post_id ) " .
" ORDER BY f.cat_id, f.forum_order";
Gruß
Olaf