Wie muss ich den folgenden Code verändern, damit es keine Probleme mehr mit dem Apostroph gibt?Could not obtain uploaded pics information
DEBUG MODE
SQL Error : 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Don' # AND pic_lock = 0 AND pic_approval = 1 ORDER BY pic_time DESC ' at line 1
SELECT pic_id, pic_title, pic_time, pic_desc FROM phpbb_album WHERE pic_username='El'Don' # AND pic_lock = 0 AND pic_approval = 1 ORDER BY pic_time DESC LIMIT 1
Line : 324
File : usercp_viewprofile.php
Code: Alles auswählen
// <!-- BEGIN Users Last Album Pic -->
$sql = "SELECT pic_id, pic_title, pic_time, pic_desc FROM " . ALBUM_TABLE . " WHERE pic_username='".$profiledata['username']."'
# AND pic_lock = 0
AND pic_approval = 1
ORDER BY pic_time DESC
LIMIT 1";
if ( !($query_result = $db->sql_query($sql)) )
{
message_die(GENERAL_ERROR, 'Could not obtain uploaded pics information', '', __LINE__, __FILE__, $sql);
}
$result = $db->sql_query($sql);
$users_last_album_pic_id = '';
$users_last_album_pic_title = '';
$users_last_album_pic_desc = '';
while ($row = $db->sql_fetchrow($result))
{
$users_last_album_pic_id = $row['pic_id'];
$users_last_album_pic_title = $row['pic_title'];
$users_last_album_pic_desc = $row['pic_desc'];
$users_last_album_pic_time = $row['pic_time'];
}
If ( $users_last_album_pic_id )
{
$users_last_album_pic = '<a href="album_showpage.php?pic_id=';
$users_last_album_pic .= $users_last_album_pic_id;
$users_last_album_pic .= '" target="_blank" class="postlink"><img style="border:solid 1px black; padding:0px;" src="album_thumbnail.php?pic_id=';
$users_last_album_pic .= $users_last_album_pic_id;
$users_last_album_pic .= '" alt="'.$users_last_album_pic_desc.'" title="'.$users_last_album_pic_desc.'" border="0" /></a>';
}
else
{
$users_last_album_pic = '';
}
// <!-- END Users Last Album Pic -->